book

Lodash Drills

Complete the following Lodash exercises. The goal is to become really good at functional programming paradigm (e.g., _.map, _.filter, _.all, _.any ...etc) and a number of really useful Lodash methods (e.g., _.find, _.pluck ... etc).

  • enter your solution in the solution block
  • utilize lodash functions as much as possible
  • no for/while loop is allowed

Familiarity with programming in this way will not only make you a super productive programmer but also will pave the way for you to learn MapReduce and MongoDB.

Examples

How many people?

Done
Data
[{name: 'John'}, {name: 'Mary'}, {name: 'Joe'}, {name: 'Ben'}]
Expected Output
4
Actual Output
4
Solution
return data.length

What are the names?

Done
Data
[{name: 'John'}, {name: 'Mary'}, {name: 'Joe'}, {name: 'Ben'}]
Expected Output
[
  "John",
  "Mary",
  "Joe",
  "Ben"
]
Actual Output
[
  "John",
  "Mary",
  "Joe",
  "Ben"
]
Solution
return _.map(data, function(d){
    return d.name
})

Exercises

What names begin with the letter J?

Done
Data
[{name: 'John'}, {name: 'Mary'}, {name: 'Joe'}, {name: 'Ben'}]
Expected Output
[
  "John",
  "Joe"
]
Actual Output
[
  "John",
  "Joe"
]
Solution
return _.map(_.filter(data, function(n) { return n.name.charAt(0) == 'J'}), function(d){
    return d.name
})

How many Johns?

Done
Data
[{name: 'John'}, {name: 'John'}, {name: 'John'}, {name: 'Ben'}]
Expected Output
3
Actual Output
3
Solution
return _.size(_.filter( data, function(n) { return n.name == 'John'}))

What are all the first names?

Done
Data
[{name: 'John Smith'}, {name: 'Mary Kay'}, {name: 'Peter Pan'}, {name: 'Ben Franklin'}]
Expected Output
[
  "John",
  "Mary",
  "Peter",
  "Ben"
]
Actual Output
[
  "John",
  "Mary",
  "Peter",
  "Ben"
]
Solution
return _.map(data,function(obj) {
                    return obj["name"].split(" ")[0];
                })

What are the first names of Smith?

Done
Data
[{name: 'John Smith'}, {name: 'Mary Smith'}, {name: 'Peter Pan'}, {name: 'Ben Smith'}]
Expected Output
[
  "John",
  "Mary",
  "Ben"
]
Actual Output
[
  "John",
  "Mary",
  "Ben"
]
Solution
return _.map(_.filter(data, function(obj) {
                    return obj.name.split(" ")[1] == 'Smith'
                } ),function(obj) {
                    return obj.name.split(" ")[0];
                })

Change the format to lastname, firstname

Done
Data
[{name: 'John Smith'}, {name: 'Mary Kay'}, {name: 'Peter Pan'}]
Expected Output
[
  {
    "name": "Smith, John"
  },
  {
    "name": "Kay, Mary"
  },
  {
    "name": "Pan, Peter"
  }
]
Actual Output
[
  {
    "name": "Smith, John"
  },
  {
    "name": "Kay, Mary"
  },
  {
    "name": "Pan, Peter"
  }
]
Solution
return _.map( data, function(n){ return {"name" : n.name.split(" ")[1] + ", "  + n.name.split(" ")[0] };})

How many women?

Done
Data
[{name: 'John Smith', gender: 'm'}, {name: 'Mary Smith', gender: 'f'}, {name: 'Peter Pan', gender: 'm'}, {name: 'Ben Smith', gender: 'm'}]
Expected Output
1
Actual Output
1
Solution
return _.size(_.filter( data, function(n){ return n.gender == 'f'}))

How many men whose last name is Smith?

Done
Data
[{name: 'John Smith', gender: 'm'}, {name: 'Mary Smith', gender: 'f'}, {name: 'Peter Pan', gender: 'm'}, {name: 'Ben Smith', gender: 'm'}]
Expected Output
2
Actual Output
2
Solution
return _.size(_.filter( data, function(n){ return n.gender == 'm' && n.name.split(" ")[1] == 'Smith' }))

Done
Data
[{name: 'John Smith', gender: 'm'}, {name: 'Mary Smith', gender: 'f'}, {name: 'Peter Pan', gender: 'm'}, {name: 'Ben Smith', gender: 'm'}]
Expected Output
true
Actual Output
true
Solution
men =  _.size(_.filter( data, function(n){ return n.gender == 'm'}))
women =  _.size(_.filter( data, function(n){ return n.gender == 'f'}))

return men > women

What is Peter Pan's gender?

Done
Data
[{name: 'John Smith', gender: 'm'}, {name: 'Mary Smith', gender: 'f'}, {name: 'Peter Pan', gender: 'm'}, {name: 'Ben Smith', gender: 'm'}]
Expected Output
"m"
Actual Output
"m"
Solution
return _.find(data, {name: 'Peter Pan'}).gender

What is the oldest age?

Done
Data
[{name: 'John Smith', age: 54}, {name: 'Mary Smith', age: 42}, {name: 'Peter Pan', age: 15}, {name: 'Ben Smith', age: 35}]
Expected Output
54
Actual Output
54
Solution
return _.last(_.sortBy(data, 'age')).age

Is it true everyone is younger than 60?

Done
Data
[{name: 'John Smith', age: 54}, {name: 'Mary Smith', age: 42}, {name: 'Peter Pan', age: 15}, {name: 'Ben Smith', age: 35}]
Expected Output
true
Actual Output
true
Solution
// use _.all
return _.all(data, function(n){ return n.age < 60 })

Is it true someone is not an adult (younger than 18)?

Done
Data
[{name: 'John Smith', age: 54}, {name: 'Mary Smith', age: 42}, {name: 'Peter Pan', age: 15}, {name: 'Ben Smith', age: 35}]
Expected Output
true
Actual Output
true
Solution
// use _.some
return _.some(data, function(n){ return n.age < 18 })

How many people whose favorites include food?

Done
Data
[{name: 'John Smith', age: 54, favorites: ['food', 'movies']},
 {name: 'Mary Smith', age: 42, favorites: ['food', 'travel']},
 {name: 'Peter Pan', age: 15, favorites: ['minecraft', 'pokemo']},
 {name: 'Ben Smith', age: 35, favorites: ['craft', 'food']}]
Expected Output
3
Actual Output
3
Solution
return _.size(_.filter(data, function(n) { return _.contains(n.favorites, 'food') } ))

Who are over 40 and love travel?

Done
Data
[{name: 'John Smith', age: 54, favorites: ['food', 'movies']},
 {name: 'Mary Smith', age: 42, favorites: ['food', 'travel']},
 {name: 'Peter Pan', age: 15, favorites: ['minecraft', 'pokemo']},
 {name: 'Joe Johnson', age: 46, favorites: ['travel', 'movies']},
 {name: 'Ben Smith', age: 35, favorites: ['craft', 'food']}]
Expected Output
[
  "Mary Smith",
  "Joe Johnson"
]
Actual Output
[
  "Mary Smith",
  "Joe Johnson"
]
Solution
return _.pluck(_.filter(data, function(n) { return _.contains(n.favorites, 'travel') && n.age > 40 }), 'name')

Who is the oldest person loving food?

Done
Data
[{name: 'John Smith', age: 54, favorites: ['food', 'movies']},
 {name: 'Mary Smith', age: 42, favorites: ['food', 'travel']},
 {name: 'Peter Pan', age: 15, favorites: ['minecraft', 'pokemo']},
 {name: 'Joe Johnson', age: 46, favorites: ['travel', 'movies']},
 {name: 'Ben Smith', age: 35, favorites: ['craft', 'food']}]
Expected Output
"John Smith"
Actual Output
"John Smith"
Solution
return _.last(_.sortBy( _.filter(data, function(n) { return _.contains(n.favorites, 'food') }), 'age')).name

What are all the unique favorites?

Done
Data
[{name: 'John Smith', age: 54, favorites: ['food', 'movies']},
 {name: 'Mary Smith', age: 42, favorites: ['food', 'travel']},
 {name: 'Peter Pan', age: 15, favorites: ['minecraft', 'pokemo']},
 {name: 'Joe Johnson', age: 46, favorites: ['travel', 'movies']},
 {name: 'Ben Smith', age: 35, favorites: ['craft', 'food']}]
Expected Output
[
  "food",
  "movies",
  "travel",
  "minecraft",
  "pokemo",
  "craft"
]
Actual Output
[
  "food",
  "movies",
  "travel",
  "minecraft",
  "pokemo",
  "craft"
]
Solution
// hint: use _.pluck, _.uniq, _.flatten in some order

return _.uniq(_.flatten(_.pluck(data, "favorites")))

What are all the unique last names?

Done
Data
[{name: 'John Smith', age: 54, favorites: ['food', 'movies']},
 {name: 'Mary Smith', age: 42, favorites: ['food', 'travel']},
 {name: 'Peter Pan', age: 15, favorites: ['minecraft', 'pokemo']},
 {name: 'Joe Johnson', age: 46, favorites: ['travel', 'movies']},
 {name: 'Ben Smith', age: 35, favorites: ['craft', 'food']}]
Expected Output
[
  "Smith",
  "Pan",
  "Johnson"
]
Actual Output
[
  "Smith",
  "Pan",
  "Johnson"
]
Solution
return _.uniq(_.map(data, function(n) { return n.name.split(" ")[1]}))